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Question

π20cos x(1+sin x)(2+sin x)dx=

A
log43
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B
log13
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C
log34
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D
None of these
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Solution

The correct option is A log43
Put sinx=t
cos x dx=dt,
so that reduced integral is 10(11+t12+t)dt=[log(1+t)log(2+t)]10
=log23log12=log43

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