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Question

π20log tan x dx= [MP PET 1999; RPET 2001, 02; Karnataka CET 1999, 2000, 01, 02]


A


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Solution

The correct option is D 0
π20log tan x dx=π20log(sin xcos x)dx
=π20log sin x dxπ20 log cos x dx=0,
{a0f(x)dx=a0f(ax)dx}

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