The correct option is A 1/41/2∫_0^π/8 sec^2 2xdx=1/4[tan 2x]^π/8_0=1/4[1]=1/4. ...

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First Fundamental Theorem of Calculus

D. None of th...

Question

$\int_{0}^{\frac{π}{8}} \frac{s e c^{2} 2 x}{2} d x =$

\frac{1}{4}

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\frac{1}{3}

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\frac{1}{2}

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N o n e o f t h e s e

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Solution

The correct option is A $\frac{1}{4}$
$\frac{1}{2} \int_{0}^{\frac{π}{8}} s e c^{2} 2 x d x = \frac{1}{4} [t a n 2 x]_{0}^{\frac{π}{8}} = \frac{1}{4} [1] = \frac{1}{4} .$

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