-12 e x 1- x -1- x 2 dx - -MNR 1990- AMU 1999- UPSEAT 2000- Pb- CET 2004-A- e2-2-eB- e-e2-2C- e2-2-eD- None of these

The correct option is C ∫_1^2 e^x ( 1/x 1/x^2 )dx= [ 1/xe^x ]^2_1 = e^2/2 e ...

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Second Fundamental Theorem of Calculus

∫12 e x 1/ x ...

Question

$\int_{1}^{2} e^{x} (\frac{1}{x} - \frac{1}{x^{2}}) d x =$ [MNR 1990; AMU 1999; UPSEAT 2000; Pb. CET 2004]

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None of these

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\int_{1}^{2} e^{x} (\frac{1}{x} - \frac{1}{x^{2}}) d x =

\int_{1}^{2} e^{x} (\frac{1}{x} - \frac{1}{x^{2}}) d x =

$\int_{- 1}^{1} x | x | d x =$ [MP PET 1990; Pb. CET 2004]

$t a n 75^{\circ} - c o t 75^{\circ}$

[MNR 1982; Pb. CET 1990, 2000]

x = 1, x = 2,

x (y - e^{x}) = sin x

2 x y = 2 sin x + x^{3}

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