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Question

31(Tan1xx2+1+Tan1x2+1x)dx=

A
π
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B
2π
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C
4π
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D
none
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Solution

The correct option is A π
31(Tan1xx2+1+Tan1x2+1x)dx=01[Tan1xx2+1+Tan1x2+1x]dx+30[Tan1xx2+1+Tan1x2+1x]dx=01π2dx+30π2dx=π2+π2(3(0))=π

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