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Question

|1910sin x dx1+x8| is less then

A
1010
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B
1011
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C
107
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D
109
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Solution

The correct option is B 1011
|1910sin x dx1+x8|1910|sin x1+x8|dx
191011+x8dx<1910dxx8
=17[x7]1910
=1710717197<17107<107

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