∫e2x [sec 2x + sec 2x.tan 2x]dx
+ C
We can clearly see that the given question is of type ∫ekx [f(kx) + f'(kx)]dx
where k = 2
∫e2x [sec 2x + sec 2x.tan 2x]dx
where f(kx) = sec 2x
and f'(kx) = sec 2x.tan 2x
Hence the answer for this will be 1kekx f(kx) + C
e2x.sec2x2 + C