The correct option is
B ![](https://infinitestudent-migration-images.s3-us-west-2.amazonaws.com/_dd411b99557958d5e68b53f3747c2be053225a3d20160623-2796-1ywh9ff.png)
The given form is one of the forms of irrational algebraic functions which is
∫1(ax+b)√cx+ddx. Now to evaluate such kind of integrals we need to substitute
cx+d=t2 So, here we’ll substitute
x−2=t2 & dx = 2t.dt
So the integral becomes
∫2t.(t2+3)t.dt =∫2(t2+3)dt (use the standard formulae)
=2√3(tan−1(t√3))+C Or
2√3(tan−1(√x−2√3))+C (Substituting t =
√x−2)