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Byju's Answer
Standard XII
Mathematics
Limit
∫π/43 π/41/1+...
Question
∫
3
π
4
π
4
1
1
+
c
o
s
(
x
)
d
x
=
2
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Solution
∫
3
π
4
π
4
1
1
+
c
o
s
(
x
)
d
x
Compute the indefinite integral:
1
1
+
c
o
s
(
x
)
d
x
=
1
s
i
n
(
x
)
−
c
o
t
(
x
)
+
C
Compute the boundaries :
∫
3
π
4
π
4
1
1
+
c
o
s
(
x
)
d
x
=
1
+
√
2
−
(
√
2
−
1
)
=
1
+
√
2
−
(
√
2
−
1
)
=
2
.
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