- dx - x -34 - 5 x -16 - 5-A- x-3x-11 - 5- cB- x-3-x-11 - 5-cC- 5-4x-3-x-11 - 5- cD- x -36 - 5 x -14 - 5- c

The correct option is C 5/4 ( x 3/x+1 )^1/5+cI = ∫dx/(x 3)^4/5(x+1)^6/5 Put t= x 3/x+1 dt = 4/(x+1)^2dx. I = 1/4∫dt/t^4/5 = 1/4 ( t^ 4/5+1/ 4/5+1 ) ...

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Byju's Answer

Standard XII

Mathematics

Standard Formulae - 2

∫ dx / x -34 ...

Question

$\int \frac{d x}{(x - 3)^{(4 / 5)} (x + 1)^{6 / 5}} =$

((x - 3) (x + 1)^{(1 / 5)}) + c

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\frac{5}{4} {(\frac{x - 3}{x + 1})}^{1 / 5} + c

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{(\frac{x - 3}{x + 1})}^{1 / 5} + c

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(x - 3)^{6 / 5} (x + 1)^{4 / 5} + c

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Solution

The correct option is B $\frac{5}{4} {(\frac{x - 3}{x + 1})}^{1 / 5} + c$
$I = \int \frac{d x}{(x - 3)^{4 / 5} (x + 1)^{6 / 5}} P u t t = \frac{x - 3}{x + 1} d t = \frac{4}{(x + 1)^{2}} d x . I = \frac{1}{4} \int \frac{d t}{t^{4 / 5}} = \frac{1}{4} (\frac{t^{- 4 / 5} + 1}{- 4 / 5} + 1) = \frac{5}{4} t^{1 / 5} = \frac{5}{4} {(\frac{x - 3}{x + 1})}^{1 / 5}$

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Similar questions

\int \frac{d x}{(x - 3)^{(4 / 5)} (x + 1)^{6 / 5}} =

\int \frac{d x}{(x - 3)^{4 / 5} (x + 1)^{6 / 5}} =

Q. Find the values of

x .

(i)

3^{x} \times 3^{- 2} = 3^{2}

(ii)

5^{- 3} \div 5^{x} = 5^{2}

(iii)

{(\frac{11}{5})}^{- 5} \times {(\frac{11}{5})}^{- 2} = {(\frac{11}{5})}^{x - 9}

Q. Complete the last column of the table: [4 MARKS]

\begin{matrix} S . N O & E q u a t i o n & V a l u e & S a y, w h e t h e r t h e e q u a t i o n i s s a t i s f i e d . (y e s / N o) (i) & x + 3 = 0 & x = 3 (i i) & x + 3 = 0 & x = 0 (i i i) & x + 3 = 0 & x = - 3 (i v) & x - 7 = 1 & x = 7 (v) & x - 7 = 1 & x = 8 (v i) & 5 x = 25 & x = 0 (v i i) & 5 x = 25 & x = 5 (v i i i) & 5 x = 25 & x = - 5 \end{matrix}

Find the value of $x$ .

$3 x + \frac{9}{3} = 5 x + \frac{5}{9}$

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∫dx(x−3)(4/5)(x+1)6/5=

The correct option is B 54(x−3x+1)1/5+cI=∫dx(x−3)4/5(x+1)6/5Put t=x−3x+1dt=4(x+1)2dx.I=14∫dtt4/5=14(t−4/5+1−4/5+1)=54 t1/5=54(x−3x+1)1/5

$\int \frac{d x}{(x - 3)^{(4 / 5)} (x + 1)^{6 / 5}} =$