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Question

π24π216 sinxxdx=

A
2
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B
12
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C
22
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D
π2
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Solution

The correct option is A 2
Put x=t12xdx=dt
x=π216t=π4,x=π24t=π2
π24π216 sinxxdx=π2π4[sin t. 2 dt=2 cost]π2π4=2[012]=2

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