wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

π2π2 cos x1+exdx=

A
0.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
-2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1
I=π2π2 cos x1+exdx=π2π2cos(x)1+exdx=π2π2 ex.cos xex1dx
2I=π2π2(1+ex)cos x1+exdx=2 0π2 cos x dx=2[sin x]π20=2I=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration of Piecewise Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon