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Question

π2π3 1+cos x(1cos x)52dx= [AI CBSE 1980]


A
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B


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Solution

The correct option is B



I=π2π31+cos x(1cos x)52×1cos x1cos xdx
=π2π3sin x(1cos x)3dx
Now, put 1 - cos~x=t
Also, when x=π3,t=12 and x=π2, t=1
Therefore, I=112dtt3=t22112=32


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