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Byju's Answer
Standard XII
Mathematics
Property 1
∫0π/4 7θsin 3...
Question
∫
π
4
0
s
e
c
7
θ
s
i
n
3
θ
d
θ
=
A
1
12
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B
3
12
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C
5
12
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D
N
o
n
e
o
f
t
h
e
s
e
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Solution
The correct option is
C
5
12
∫
π
4
0
s
e
c
7
θ
s
i
n
3
θ
d
θ
=
∫
π
4
0
s
i
n
3
θ
c
o
s
3
θ
.
s
e
c
4
θ
d
θ
Putting tan
θ
= t, it reduces to
∫
1
0
t
3
(
1
+
t
2
)
d
t
∣
∣
t
4
4
+
t
6
6
∣
∣
1
0
=
5
12
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