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Question

π2π4 cos θ cosec2θ dθ=

A
21
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B
12
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C
2+1
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D
None of these
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Solution

The correct option is A 21
Let π2π4cos θ1sin2θdθ
Put t=sin θdt=cos θ dθ, then we have
1121t2dt=[1t]112=21

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