You visited us 1 times! Enjoying our articles? Unlock Full Access!

Beta Decay

Th-230 underg...

Question

$T h - 230$ undergoes a series of radioactive decay processes resulting in $B i - 214$ being the final product. What was the sequence of the processes that occurred?

α, α, α, g, β

No worries! We‘ve got your back. Try BYJU‘S free classes today!

α, α, α, α, β

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

α, α, β, β

No worries! We‘ve got your back. Try BYJU‘S free classes today!

α, β, β, β, γ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $α, α, α, α, β$
For $α$ decay : $_{Z}^{A} X \to_{Z - 2}^{A - 4} Y$
For $β$ decay : $_{Z}^{A} X \to_{Z + 1}^{A} Y$
For $γ$ decay: $_{Z}^{A} X \to_{Z}^{A} X^{}$ ( means excited sate )
Here change in mass number $= 230 - 214 = 16$
From above equation we can say it is possible when 4 alpha decay will happen. So the option B is correct.

Suggest Corrections

Similar questions

Z = 92

α, α, β^{-}, β^{-}, α, α, α, α, β^{-}, β^{-}, α, β^{+}, β^{+}, α

Z

Z = 92

α, α, β^{-}, β^{-}, α, α, α, α; β^{-}, β^{-}, α, β^{+}, β^{+}, α

Z

Z = 92

α, β^{-}, β^{-}, α, α, α, α, α, β^{-},

β^{-}, α, β^{+}, β^{+}, α

Z

α, β^{-}, β^{-}, α, α, α, α, α, β^{-}, β^{-}, α, β^{+}, β^{+}, α,

Z = 92

α, β -, β -, α, α, α, α, α, β -, β -, β +, α, β +, α

Z

Join BYJU'S Learning Program