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Beta Decay

Th-230 underg...

Question

$T h - 230$ undergoes a series of radioactive decay processes resulting in $B i - 214$ being the final product. What was the sequence of the processes that occurred?

α, α, α, g, β

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α, α, α, α, β

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α, α, β, β

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α, β, β, β, γ

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Solution

The correct option is B $α, α, α, α, β$
For $α$ decay : $_{Z}^{A} X \to_{Z - 2}^{A - 4} Y$
For $β$ decay : $_{Z}^{A} X \to_{Z + 1}^{A} Y$
For $γ$ decay: $_{Z}^{A} X \to_{Z}^{A} X^{}$ ( means excited sate )
Here change in mass number $= 230 - 214 = 16$
From above equation we can say it is possible when 4 alpha decay will happen. So the option B is correct.

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