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Question

Th moment of inertia of a rod of mass M and length L about an axis passing through on edge of perpendicular to its length will be :-

A
ML212
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B
ML26
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C
ML23
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D
ML2
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Solution

The correct option is C ML23

Given,

Mass of rod =M

Length of Rod =L

Distance of rods edge from center =L2

Moment of inertia of rod at center Ic=112ML2

For moment of inertia at edge apply parallel axis theorem. Ie=Ic+M(L2)2

I=112ML2+M(L2)2=13ML2

moment of inertia at edge is 13ML2


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