Th value of (sinθ+cscθ)2+(cosθ+secθ)2−(tan2θ+cot2θ) is
By expanding the expression we get
(sinθ+cscθ)2+(cosθ+secθ)2−(tan2θ+cot2θ)
=sin2θ+csc2θ+2+sec2θ+cos2θ+2−tan2θ−cot2θ
=4+(sin2θ+cos2θ)+(csc2θ−cot2θ)+(sec2θ−tan2θ)
=4+1+1+1=7
Hence answer is D