That part of area which is bounded by $C_{1}$ and $C_{2}$ but not bounded by $C_{3}$ and $C_{4}$ has area

1

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\frac{1}{2}

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\frac{1}{3}

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None of these

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Solution

The correct option is A $1$
From the figure, are of the yellow square is the area bounded by $C_{1}$ and $C_{2} = 2$
The area bounded by $C_{3}$ and $C_{4} = 1$
Therefore, area bounded by $C_{1}$ and $C_{2} = 2 - 1 = 1$

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