That the child has exactly $50$ toys.

\frac{63}{200}

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\frac{53}{200}

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\frac{63}{100}

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\frac{53}{100}

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Solution

The correct option is D $\frac{63}{200}$
Total no. of childrens $= 3 + 8 + 20 + 15 + 6 + 12 + 18 + 11 + 22 + 17 + 15 + 10 + 13 + 10 + 10 + 10 = 200$

$P (F) = \frac{No. of childrens having exactly 50 toys}{Total no. of childrens}$

$= \frac{20 + 18 + 15 + 10}{200} = \frac{63}{200}$

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