Question

The $10th$ and $18th$ terms of an A.P are $41$ and $73$ respectively. Find the $26th$ term ?

Answer 1

$T_n=a+(n-1)d$
Where $a$ is the first term, $d$ is the common difference and $T_n$ denotes the n-th term of an AP.
Given:
$41=a+9d$
$73=a+17d$
Solving the above two equations gives: $d=4,a=5$
Therefore, $T_{26}=6+25\cdot 4=106$