The 10th common term between the A.P.s 3, 7, 11, 15, .... and 1, 6, 11, 16, ... is
191
As, the common difference of the A.P. 3, 7, 11, 15, ... = 7 - 3 = 4 and the common difference of the A.P. 1, 6, 11, 16, ... = 6 - 1 = 5
And, the common terms of both the A.P.s will be in A.P.
So, the common difference of the A.P. of the common terms, d = LCM (4, 5)
=4×5=20 and its first common term,
a = 11
Now, the tenth common term, a10=a+(10−1)d
=11+9×20
=11+180=191
Hence, the correct alternative is option (a).