Question

The 11th term from the end of the A.P. 10, 7, 4, .........., -62 is :

• A. 25
• B. 30
• C. -32
• D. 35

Answer 1

The correct option is C -32

The sequence given is 10, 7, 4, ....-62.
First we need to find out number of terms in this sequence.
'a' = 10, 'd' = -3, last term = -62
$t_n=a+(n-1)d⟹-62=10+(n-1)(-3)⟹-62=13-3n⟹3n=75orn=25$.
The number of terms in the sequence is 25.
The 11th term from the end is same as the 15th term from the first.
So, $t_{15}=10+(15-1)(-3)⟹t_{15}=10+\left(14\right)(-3)⟹t_{15}=-32$.
The 11th term from the end is -32.