The 17th term of an AP exceeds its 10th term by 7. Its common difference is
It is given that 17th term exceeds its 10th term by 7
It means a17 = a10 + 7......(1)
Here, a17 is the 17th term and a10 is the 10th term of an AP.
Using formula an=a+(n−1)d to find nth term of arithmetic progression, we get
a17=a+(16)d .....(2)
a10=a+(9)d .....(3)
Putting (2) and (3) in equation (1), we get
a+16d=a+9d+7
⇒7d=7
⇒d=77=1