Question

The 1st three common multiple of numbers $12,8,16$ are

• A. $12,24$
• B. $8,16$
• C. $16,32$
• D. $48,96$

Answer 1

The correct option is D $48,96$

Multiples of 12 are 12,24,36,48,60,72,84,96,108,120......

Multiples of 8 are 8,16,24,32,40,48,56,64,72,80,88,96.......

Multiples of 16 are 16,32,48,64,80,96..........

$\therefore$ First two common multiples $=48,96$