The 20th term of the series 2 - 4-4 - 6-6 - 8- will be

The correct option is B 1680 The given series 2×4+4×6+6×8+......... n^th terms T_n = 2n.2(n+1) = 4n(n+1) Putting n = 20, we get T_20 = 4.20(20 + 1) = 1680 ...

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Standard XII

Mathematics

Series

The 20th term...

Question

The $20^{t h}$ term of the series 2 $\times$ 4+4 $\times$ 6+6 $\times$ 8+......... will be

1600

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1680

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420

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840

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Solution

The correct option is B
1680

The given series 2 $\times$ 4+4 $\times$ 6+6 $\times$ 8+......... $n^{t h}$ terms

$T_{n}$ = 2n.2(n+1) = 4n(n+1)

Putting n = 20, we get $T_{2} 0$ = 4.20(20 + 1) = 1680

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Similar questions

Find the 20^th term of the series 2 × 4 + 4 × 6 + 6 × 8 + … + n terms.

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Q. Find the 20^th term and the sum of 20 terms of the series 2 × 4 + 4 × 6 + 6 × 8 + ...

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The 20th term of the series 2×4+4×6+6×8+......... will be

The correct option is B 1680 The given series 2×4+4×6+6×8+......... nth terms Tn = 2n.2(n+1) = 4n(n+1) Putting n = 20, we get T20 = 4.20(20 + 1) = 1680

The $20^{t h}$ term of the series 2 $\times$ 4+4 $\times$ 6+6 $\times$ 8+......... will be

The correct option is B
1680

The given series 2 $\times$ 4+4 $\times$ 6+6 $\times$ 8+......... $n^{t h}$ terms

$T_{n}$ = 2n.2(n+1) = 4n(n+1)

Putting n = 20, we get $T_{2} 0$ = 4.20(20 + 1) = 1680