Question

The ${2006}^{th}$ digit in the sequence $12345678910111213$.....is

• A. $4$
• B. $7$
• C. $0$
• D. $5$

Answer 1

The correct option is C $0$

All the natural numbers starting from $1$ are enlisted:

So number of $1$ digit numbers $=9$

Number of $2$ digit numbers $=90$

To calculate number of digits we need to multiply by $2$

Number of $3$ digit numbers starting from $100$ till $699=600$(to calculate number of digits we need to multiply by $3$)

So, starting from $1$ to $699$, total number of digits will be

$9+2\times 90+3\times 600=1989$.

If we also add $700-704$ we get total $1989+15=2004$ digits enlisted.

Now the $2006$ digit in the sequence is clearly evident that would be the second digit of $705$ which is $0$.