The 20th term from the last of arithmetic sequence 5, 10, 15, 20..... 150 will be

25

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45

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55

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85

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Solution

The correct option is C $55$
Common difference = -5 (as we need term from last)
20th term from the last = $150 + (20 - 1) \times - 5 = 55$

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Similar questions

20^{t h}

\frac{1}{5}, \frac{1}{10}, \frac{1}{15}, \frac{1}{20} . . . . . \frac{1}{150}

Rent (in Rs)	$15 - 25$	$25 - 35$	$35 - 45$	$45 - 55$	$55 - 65$	$65 - 75$	$75 - 85$	$85 - 95$
No. of Houses	$8$	$10$	$15$	$25$	$40$	$20$	$15$	$7$

The 10th term of an arithmetic sequence is 65 and its 15th term is 20. Then 20th term is

5 + 15 + 25 + 35 + 45 + 55 + 65 + 75 + 85 + 95 = ___

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