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Question

Question 6
The 21st term of an AP whose first two terms are – 3 and 4, is

A) 17
B) 137
C) 143
D) -143

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Solution

Given, the first two terms of the AP are :
a = -3 and
a + d = 4.

3+d=4
d=7
a21=a+(211)d [an=a+(n1)d]
a21=3+(20)7
a21=3+140=137

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