Question

The ${}^{238}U$ consumed in a day in an atomic power house operating at $400MW$, provided the whole of mass ${}^{235}U$ is converted into energy is :

• A. $0.294kg$
• B. $0.423kg$
• C. $0.216kg$
• D. $0.326kg$

Answer 1

The correct option is B $0.423kg$

$P=4\times {10}^{8}J/s$
E required for whole day $=4\times 24\times 60\times 60\times {10}^{8}J$
$=3.456\times {10}^{13}J$
$3.456\times {10}^{13}=\frac{m}{235}\times 6\times {10}^{23}\times 200\times 1.6\times {10}^{-13}$
$0.423\times {10}^{3}g=m$

$m=0.423kg$