Consider the given A.P. series
10,7,4........
a=10
d=7−10=−3
n=30
Find a30
We know that, an=a+(n−1)d
a30=10+(30−1)×(−3)
a30=10−87
a30=−77Comparing −b=−77⇒b=77
Hence, this is the answer.
30th term of the AP: 10,7,4,..., is