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Question

The 31st term of the AP whose first two terms are respectively 2 and 7 is

A
152
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B
150
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C
148
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D
148
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Solution

The correct option is A 152
Given, a1=2,a2=7
d=a2a1=7(2)=7+2=5
Since, an=a+(n1)d
a31=a+30d=2+30(5)=152
Option A is correct.

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