The 35 kilogram girl is standing on a 20 kilogram wagon and jumps off, giving the wagon a kick that sends it off at 3.8 meters per second. How fast is the girl moving?

1.2 m/s

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3 m/s

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4 m/s

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2.2 m/s

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Solution

The correct option is D 2.2 m/s
Answer is D.
The total momentum is initially zero, and must remain zero. Therefore, the momentum acquired by the wagon in one direction equals the momentum acquired by the girl in the other case.
That is, ${(m v)}_{g i r l} = {(m v)}_{w a g o n}$ .
${35 k g \times (v)}_{g i r l} = 20 k g \times 3.8 m / s$ .
Therefore, ${(v)}_{g i r l} = 2.2 m / s$ .
Hence, the girl is moving at a velocity of 2.2 m/s.

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