Question

The 4 term of a H.P is $\frac{3}{5}$ and 8th term is $\frac{1}{3}$, then its 6th term is

• A. $\frac{1}{6}$
• B. $\frac{3}{7}$
• C. $\frac{1}{7}$
• D. $\frac{3}{5}$

Answer 1

The correct option is B

$\frac{3}{7}$

a + 3d = $\frac{5}{3}$ and a + 7d = 3

Solving a = $\frac{2}{3}$, d = $\frac{1}{3}$

6th term of A.P = a + 5d = $\frac{2}{3}+\frac{5}{3}$ = $\frac{7}{3}$

$\Rightarrow$ 6th term of H.P. = $\frac{3}{7}$.