The 4th,7th and 10th term of a G.P. are a,b,c respectively, then
A
a2=bc
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B
b2=ac
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C
c2=ab
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D
ab2=c
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Solution
The correct option is Bb2=ac Let A be the first term and r be the common ratio of the given G.P.
Then, a=Ar(4−1)=Ar3;b=Ar(7−1)=Ar6 and c=Ar(10−1)=Ar9 ∴ac=(Ar3)×(Ar9)=A2r12=(Ar6)2=b2
Hence, b2=ac.