Question

The $4^{th}$ term of the sequence defined by $t_n=\frac{1+(-2{)}^n}{n-1}$ is

• A. $\frac{14}{3}$
• B. 7
• C. $\frac{17}{3}$
• D. 8

Answer 1

The correct option is C $\frac{17}{3}$

Given: $t_n=\frac{1+(-2{)}^n}{n-1}$
$\therefore 4^{th}$ term, $t_4=\frac{1+(-2{)}^4}{4-1}=\frac{1+16}{3}=\frac{17}{3}$
Hence, the correct answer is option (3).