Question

The 4th term from the end of AP −11, −8, −5, ... ,49 is
(a) 58
(b) 43
(c) 40
(d) 37

Answer 1

(c) 40

Here, a = -11 and d = [-8 - (-11)] = 3, l = 49 and n = 4^th
Now, n^th term from the end = [l - (n - 1)d]
4^th term from the end = [49 - (4 - 1) ⨯ 3]
= [49 - (3 ⨯ 3)] = (49 - 9) = 40
Hence, the 4^th term from the end of the AP is 40.