The 4th term of the AP -8- -18- -32- is

The correct option is B 5 √(2)a_n = a+(n 1)d Given a = nbsp;√(8) nbsp;and d = √(18) √(8) a_4 = √(8) + (4 1)(√(18) √(8)) a_4 = 2√(2) + (4 1)(3√(2) 2√ ...

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Byju's Answer

Standard VIII

Mathematics

nth term of an AP

The 4th term ...

Question

The 4th term of the $A P \sqrt{8}, \sqrt{18}, \sqrt{32}$ .... is ____.

5 \sqrt{2}

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5 \sqrt{3}

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3 \sqrt{3}

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5 \sqrt{5}

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Solution

The correct option is A $5 \sqrt{2}$
$a_{n} = a + (n - 1) d$
Given $a = \sqrt{8}$ and d = $\sqrt{18} - \sqrt{8}$
$a_{4} = \sqrt{8} + (4 - 1) (\sqrt{18} - \sqrt{8}) a_{4} = 2 \sqrt{2} + (4 - 1) (3 \sqrt{2} - 2 \sqrt{2}) a_{4} = 2 \sqrt{2} + 3 (\sqrt{2}) a_{4} = 5 \sqrt{2}$

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Similar questions

Write the next term of the $A P : \sqrt{8}, \sqrt{18}, \sqrt{32}, . . . .$

Q. What is the next term of the AP

\sqrt{2}, \sqrt{8}, \sqrt{18},

____?

\sqrt{8}, \sqrt{18}, \sqrt{32}

are in AP. Find the next term and common difference.

Q. Find first term 'a' and common difference 'd' for the following AP.

\sqrt{2}

\sqrt{8}

\sqrt{18}

\sqrt{32}

,.....

Q. The

4^{th}

and

9^{th}

terms of an AP are 18 and 68 respectively. The sum of the first 10 terms of the AP is .

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The 4th term of the AP√8,√18,√32.... is ____.

The correct option is A 5√2an=a+(n−1)d Given a=√8 and d = √18−√8 a4=√8+(4−1)(√18−√8)a4=2√2+(4−1)(3√2−2√2)a4=2√2+3(√2)a4=5√2

The 4th term of the $A P \sqrt{8}, \sqrt{18}, \sqrt{32}$ .... is ____.

The correct option is A $5 \sqrt{2}$
$a_{n} = a + (n - 1) d$
Given $a = \sqrt{8}$ and d = $\sqrt{18} - \sqrt{8}$
$a_{4} = \sqrt{8} + (4 - 1) (\sqrt{18} - \sqrt{8}) a_{4} = 2 \sqrt{2} + (4 - 1) (3 \sqrt{2} - 2 \sqrt{2}) a_{4} = 2 \sqrt{2} + 3 (\sqrt{2}) a_{4} = 5 \sqrt{2}$