The 5th term of an AP is -3 and its common difference is -4. The sum of its first 10 terms is
(a) 50 (b) -50 (c) 30 (d) -30

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Solution

T5=-3
D=-4
T5=a+(n-1)d=-3
a-16=-3
a=13
sum=n/2{2a+(n-1)d}
=5(26-36)
=-50

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