The $6^{t h}$ term from the end of the AP: 5, 2, -1, -4 ... ...., -31 is

-16

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-19

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-22

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-25

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Solution

The correct option is A -16
The given AP is $5, 2, - 1, - 4 . . . . . . ., - 31$
Reverse A.P. $= - 31, . . . . . . . . . . . - 4, - 1, 2, 5$
Difference, $d = 5 - 2 = 3$
The first term $= a = - 31$
We know, $a_{n} = a + (n - 1) d$
$a_{6} f r o m t h e e n d = - 31 + (6 - 1) 3$
$= - 31 + 15$
$a_{6} f r o m t h e e n d = - 16$

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