The correct option is D 15th term of AP is −46
Let a and d be the first term and common difference of the given AP respectively.
∴a6=−10⇒a+5d=−10 ...(1)
& a10=−26⇒a+9d=−26 ...(2)
On subtracting (1) from (2), we get
4d=−16⇒d=−4
Putting d=−4 in (1), we get
a=−10−(5×−4)=10
Now, a15=a+14d=10+14×−4=−46
Hence, 15th term of the given AP is −46.