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Question

The 8th term of an A.P. is 17 and the 19th term is 39. Find the 25th term.

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Solution

Given that: T8=17,T19=39,T25=?
To find T25, first we should find a and d.
d=TpTqpq
d=T19T8198=391711=2211d=2
Consider,
T8=17
a+7d=17 [Tn=a+(n1)d]
a+7(2)=17
a+14=17
a=3
To find T25,Tn=a+(n1)d
T25=3+(251)2=3+(24×2)=3+48
T25=51

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