Question

The $8^{th}$ term of an AP is $37$ and its ${12}^{th}$ term is $57$. Find the AP.

Answer 1

$8term=37$ , given series is A.P.

$a+7d=3712term=57a+11d=57(a+11d)-(a+7d)=57-374d=20d=5a+35=37=>a=2A.Pis2,7,12,17,....$