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Question

The 9th term of an AP is 499 and 499th terms is 9. The term which is equal to zero is

A
501th
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B
502th
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C
508th
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D
None of these
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Solution

The correct option is C 508th
a9=a+8d
a9=499(given)
a+8d=499.........(i)
a499=a+498d
a499=9
a+498d=9.........(ii)
Subtract (i) from (ii)
490d=490
d=1
substitute the value of d
a+8(1)=499
a=507
For an=0
a+(n1)d=0
507+(n1)(1)=0
507=n1
n=508
So, 508th term is equal to zero.

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