The 9th term of an AP is equal to 7 times the second term and 12 term exceeds 5 times the third term by 3 find the first term and the common difference
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Solution
let the first term be a and common difference be d. a9=7a2 a+8d =7(a+d) -6a+d =0 ........(1) a12=5a3+2 a+11d = 5(a+2d)+2 -4a +d = 2 ........(2) subtrating (2) from (1) -2a = -2 a=1 substituting in (1) -6+d=0 d=6