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Question

The A.M. of first n terms of the series 1.3.5, 3.5.7, 5.7.9,....., is

A
3n3+6n2+7n1
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B
n3+8n2+7n1
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C
2n3+8n27n2
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D
2n3+8n2+7n2
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Solution

The correct option is D 2n3+8n2+7n2

Tn=(2n1)(2n+1)(2n+3)


Req. A.M.

=Snn=Tnn=1n[(8n3+12n22n3)]


=1n[8n3+12n22n3]


=2n3+8n2+7n2


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