Question

The above data is the sale of the donuts for a week. The probability of finding atleast one of the donut that will be sold in the next two sales is .

• A. 0.6%
• B. 60%
• C. 30%

Answer 1

The correct option is B 60%

Given,

The probability that a donut is sold on a given day is 20%.
20% of 10 numbers is 2 numbers.

In the trials given, we have numbers containing the digits 1, 2, 3, 4, 5 and 6.

Let say numbers 1 and 2 are assigned for the sale of donuts.

All the numbers containing either or both of the digits 1 and 2 has been highlighted.

So, total number of favorable outcomes is 6.


P(atleast one of the donut sold in next $\text{two sales)}=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$

$=\frac{6}{10}$

$=\frac{3}{5}\times 100$

$=60\%$