The above figure gives the graph between grades and and number o students in the subject of history. What is the mean history GPA for this class of students?

2.0

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2.5

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2.6

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3.0

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Solution

The correct option is A $2.5$
Each segment on the $y$ axis accounts for $1$ student.
Hence, the mean GPA = $\frac{\sum N (i) C (i)}{N} = \frac{(10 \times 4) + (3 \times 36) + (2 \times 28) + (8 \times 1) + (0 \times 2)}{84}$
$= \frac{40 + 108 + 56 + 8}{84}$
$= \frac{212}{84}$ $= 2.52$

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The above figure gives the graph between grades and and number o students in the subject of history. What is the mean history GPA for this class of students?

The correct option is A 2.5Each segment on the y axis accounts for 1 student. Hence, the mean GPA =∑N(i)C(i)N=(10×4)+(3×36)+(2×28)+(8×1)+(0×2)84 =40+108+56+884=21284 =2.52

The correct option is A $2.5$
Each segment on the $y$ axis accounts for $1$ student.
Hence, the mean GPA = $\frac{\sum N (i) C (i)}{N} = \frac{(10 \times 4) + (3 \times 36) + (2 \times 28) + (8 \times 1) + (0 \times 2)}{84}$
$= \frac{40 + 108 + 56 + 8}{84}$
$= \frac{212}{84}$ $= 2.52$