The above figure is a square- The value of x 1- y 1- x 2- y 2- x 3- y 3 isA- 0B- aC- 2 zD- - 2 a

The correct option is D 2a We know that, Y coordinates below x axis nbsp;have negative value whereas above x axis they have positive value. So, B = (a, a) ...

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The above fig...

Question

The above figure is a square. The value of $x_{1} + y_{1} + x_{2} + y_{2} + x_{3} + y_{3}$ is

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Solution

The correct option is D
-2a

We know that,

Y coordinates below x-axis have negative value whereas above x-axis they have positive value.

So, B = (a, -a), C = (-a, -a) and D = (-a, a)
The value of $x_{1} + y_{1} + x_{2} + y_{2} + x_{3} + y_{3}$ = $a + (- a) + (- a) + (- a) + (- a) + a$ = $- 2 a$

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The above figure is a square. The value of x1+y1+x2+y2+x3+y3 is

The correct option is D -2a We know that, Y coordinates below x-axis have negative value whereas above x-axis they have positive value. So, B = (a, -a), C = (-a, -a) and D = (-a, a) The value of x1+y1+x2+y2+x3+y3 = a+(−a)+(−a)+(−a)+(−a)+a = −2a

The above figure is a square. The value of $x_{1} + y_{1} + x_{2} + y_{2} + x_{3} + y_{3}$ is

The correct option is D
-2a

We know that,

Y coordinates below x-axis have negative value whereas above x-axis they have positive value.

So, B = (a, -a), C = (-a, -a) and D = (-a, a)
The value of $x_{1} + y_{1} + x_{2} + y_{2} + x_{3} + y_{3}$ = $a + (- a) + (- a) + (- a) + (- a) + a$ = $- 2 a$